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dsc
10-02-2013, 08:40 PM
Gents,

I'm trying to calculate the maximum deflection of an unsupported part of a shaft with the following data:

L total unsupported length = 0.18m (not mm;))
A cross section surface (round rod) = pi * (0.01m)^2
E Young's modulus = 180GPa
F force applied to the end of shaft = 1000N (random round number)

delta (max deflection) = F*L / E*A

Now popping the values in to the equation I get that max deflection is equal:

delta = F * 3.19*10^-9 [m/N]

which basically means that with F = 1000N the deflection is

delta = 3.19 * 10^-6 m = 3.19*10^-3 mm = 0.00319mm

That is rather small, considering that 1000N is pretty much the same as 100kg weight attached to one end.

Pack of biscuits to anyone who can point an error in the above and call be stupid:)

Regards,
dsc.

m_c
10-02-2013, 09:12 PM
0.18mm unsupported length?

dsc
10-02-2013, 09:30 PM
Ha, well spotted, although it's just a unit error.

After some reading I don't think the above equation for delta is correct as there's no moment of inertia involved.

Regards,
dsc.

m_c
10-02-2013, 09:40 PM
I just ran the figures and got 3183mm of deflection...

A = pi0.01^2 = 0.000314159
F*L = 1000 * 0.18 = 180
E*A = 180 * 0.0003blahblah = 0.05654866

180 / 0.0565blahblah = 3183.09886183

Robin Hewitt
10-02-2013, 11:47 PM
Perhaps you are working out how far it will stretch if you pull on the end, not how far it will bend if you load it at 90 degrees?

Web Goblin
11-02-2013, 06:18 AM
You could be right here Robin. Its been a very long time since I used Youngs Modulus but in this form I thought it was used for calculating a change in length due to compression or extension.

dsc
11-02-2013, 08:33 AM
Ah yes, it's all wrong!:)

Here's the right formula (taken from http://www.clag.org.uk/beam.html):

δ = FL3 ∕ 3EI

I = πr4 ∕ 4 = πd4 ∕ 64

(for round beam)
which means that deflection at a given F and L, for a 20mm dia beam is:

δ = FL3 * 0.0002358

Assuming L = 0.18m and F=100N the maximum deflection is:

δ = 100 * 0.005832 * 0.0002358 m = 0.0001375m = 0.1375mm

Which makes much more sense than the previously calculated value.

The funny thing is that changing the dia from 20mm to 22mm gives you a maximum deflection drop from 0.1375mm to 0.094mm. That's just by making the shaft 2mm thicker. Quite amazing me thinks.

Regards,
dsc.