Confused again!

[Buba b]

So i finally had enough of Mach 3 and while sitting with a broken collar bone i got carried away ! So i splashed the cash on new Adtech 9640 controller while on pain killers and this turned up a month later . Some months later i decided to use it and then got confused again !.


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So my problem is making it count to 10 , its a recurring problem I've had with all the systems I've ever put together .
The Am882 are set to 8 micro stepping on 5mm pitch screws , I test cut at 55mm long and get 58mm at the moment .....so

Gear numerator / Gear denominator = P ( L x 1000 ) = a magic number

5x1000=5000/1600 =3.20

Its just that I cant get a decimal point into the Gear denominator parameter which means I've messed up some where !


Anyone have experience of setting these controllers up
Someday this will cut metal ........... just not today !
Thanks

[dazp1976]

Is 8 micro stepping equivelent to 1600? Can't remember.

Well in Mach3 for example you'd:
1. Have 1600 per rev on the drive.
2. Then divide that by the pitch (5)..
3. Mach = 320 per unit.

How that system you have now works is beyond me.
Do you have any documentation for setting it up?


Is that power drawbar custom built?
Looks good and I wouldn't mind having the drawings for future reference if poss :)

[johngoodrich]

I agree with daz above. I had a look at the manual and it doesn't say what the numerator and denominator are meant to be or for that matter P and L in your equation above. I would presume the numerator would be the steps per rev(1600) and the denominator would be the pitch of your screw(5). What figures have you got in there already to make it move 58mm?

[Buba b]

So I've just sorted my duff maths in first post ! And it proves I can't make tea and post at the same time , anyways the manual gives an example of a servo :
Motor rotates one cycle every 5000 pulses and tool moves 10mm
CMR/CMD = 5000/(10x1000) = 1/2
CMR : Gear ratio numerator
CMD : Gear rato denominator

I'm running at 1/3 which gives me the 3mm over run , if your right and I need to put in 1600/5 then that would be great as I wouldn't have to frazzle my brain with maths. They just look big numbers compared to the manual and I never thought about it that way . Il try tomorrow see what happens .... Can't be that easy , it's Chinese !
Thanks

[johngoodrich]

So I've just sorted my duff maths in first post ! And it proves I can't make tea and post at the same time , anyways the manual gives an example of a servo :
Motor rotates one cycle every 5000 pulses and tool moves 10mm
CMR/CMD = 5000/(10x1000) = 1/2
CMR : Gear ratio numerator
CMD : Gear rato denominator

I'm running at 1/3 which gives me the 3mm over run , if your right and I need to put in 1600/5 then that would be great as I wouldn't have to frazzle my brain with maths. They just look big numbers compared to the manual and I never thought about it that way . Il try tomorrow see what happens .... Can't be that easy , it's Chinese !
Thanks

I would say yes it seems that would be right from their example, apart from where they put =1/2 because that doesn't add up but that could just be because its Chinese translation give it a try and let us know

[JAZZCNC]

I haven't seen the manual but I think you may be using the wrong parameter. Usually, Numerator/Denominator relates to gearing, it's often used in servos for electronic gearing.
So in your case, if you have no gearing then it will be 1/1. The actual pulse setting I'd expect to be in another parameter, often it's the encoder pulse parameters that dictate the output pulses per unit(mm) so it could be you need to enter 320 into the encoder parameters.? (might need to divide this by 4 if the parameter expects encoder base count as it will multiply x4 as it will assume your using quadrature encoders.!)

But without seeing the manual I could be way off.!!

[johngoodrich]

Listen to jazz. He knows what hes talking about

[dazp1976]

I haven't seen the manual but I think you may be using the wrong parameter. Usually, Numerator/Denominator relates to gearing, it's often used in servos for electronic gearing.
So in your case, if you have no gearing then it will be 1/1. The actual pulse setting I'd expect to be in another parameter, often it's the encoder pulse parameters that dictate the output pulses per unit(mm) so it could be you need to enter 320 into the encoder parameters.? (might need to divide this by 4 if the parameter expects encoder base count as it will multiply x4 as it will assume your using quadrature encoders.!)

But without seeing the manual I could be way off.!!

I was thinking that last night.
The gearing is for if you are driving your motors/screws with reduction such as 2/1 belt & pulley. 1/1 being direct drive with no pulleys.

[m_c]

I think you need to change the encoder wire parameter (2-29)

I did try attaching the PDF, but I think it's too big for the forum to accept :-/

[Buba b]

So I've had a little play and its still not playing ball but its hotter than the sun in my garage at the moment and il have wait until its cooler then hit it.
By memory in the Fanuc manual the numerator and denominator are used for gear reduction and in the Adtech the manual states :

" When screws of different pitches and motors of different step angles or servo motors of different pulses are matched or connected through gears it allows keeping the program and actual motion distance consistent through electronic gear ratio setting of the system. "

So I've thought this meant by the first part of the statement that the motors and pitch ( with the calculation ) would be needed for the setup but you could also read into the second part , that this setting is for gearing the motion . Even reading Fanuc manuals usually leaves you scratching your head if you overthink the use of English and this manual is no better.
With the quick go the 1/1 its not even close to measurement and 1600/320 was interesting until it didn't move at all , but i need to get in and play more when cooler and have another scan through the manual .
Thanks