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10-02-2013 #1
Gents,
I'm trying to calculate the maximum deflection of an unsupported part of a shaft with the following data:
L total unsupported length = 0.18m (not mm;))
A cross section surface (round rod) = pi * (0.01m)^2
E Young's modulus = 180GPa
F force applied to the end of shaft = 1000N (random round number)
delta (max deflection) = F*L / E*A
Now popping the values in to the equation I get that max deflection is equal:
delta = F * 3.19*10^-9 [m/N]
which basically means that with F = 1000N the deflection is
delta = 3.19 * 10^-6 m = 3.19*10^-3 mm = 0.00319mm
That is rather small, considering that 1000N is pretty much the same as 100kg weight attached to one end.
Pack of biscuits to anyone who can point an error in the above and call be stupid:)
Regards,
dsc.Last edited by dsc; 10-02-2013 at 10:29 PM.
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