Thread: Stepping down from 5v to 3-4.5v
I have a cross line laser module to fit on my machine. My bob outputs a regulated 5v but the laser can only handle 3 to 4.5v.
I imagine I need some sort of inline resistor to drop the 5v to 4.5v?
Question is what value resistor?
or is there a better way?
I know I could use 3 x 1.5v batteries but I'd like an onboard solution I can control from a macro via Mach.
Many thanks for any and all help.
Regards, JeffNothing is foolproof......to a sufficiently talented fool!
I'll use three batteries and a relay.
JeffNothing is foolproof......to a sufficiently talented fool!
Just put a silicon diode (e.g. 1N4001) in series with the laser supply, it will drop a fairly consistant 0.7v. Use two, if you want to be on the safe side.
14-03-2009 #4Nothing is foolproof......to a sufficiently talented fool!
Bill's solution is the simplest and easiest to get a 0.7v drop at up to 1A (for an 1N4001 diode, although any of the 1N400x range will do). If you need more than 1A then 1N5059 series is good for 2A and 1N5624 series for 3A.
I'v just recived mine from tiwan a few days ago, i was saving it to make a post about the idea of using one :). O Well :D
Check these out:
Inductors, Capacitors & Resistors
Components: Diodes, Resistors, Capacitors, Transistors & LED
You may also like this: Resistor Calculator.Me
I won't utter another word on the subject, forget I mentioned it everybody, in fact i don't even know what a laser is. :D
Jeff. (fast running out of inputs and outputs:p)Nothing is foolproof......to a sufficiently talented fool!
lolol. Will do, you feel free to post what you want mate. It will be a few week before i cang et to play with it..Me
<noob mode> What's the laser for? </noob mode>
Better to use 2 diodes in series - they can give a different voltage drop dependent on current flow.
If you don't need to run the laser for a long duration (assuming it's for alignment of some kind) the batteries/relay idea is safer.
Well, I've got a 5v regulated PSU and a relay board so I'll try your suggestion of the two diodes (100 just arrived from the Bay :) )
Thank you everyone for the help.
Jeff.Nothing is foolproof......to a sufficiently talented fool!
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