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23-11-2010 #1
I've decided on my router that I'm going to use supported linear bearing rails on the X-axis. Two parallel rails, with two bearings on each fixed to the gantry.
Let:
- x = distace between two bearings
- F = horizontal cutting force parallel to X axis
- m = mass of gantry
- Z = distance from cutter to centre point of Z axis linear bearings.
- z = distance from X linear bearings to X axis leadscrew.
Max value = m*g/4 + F/(2x)*(Z+z)
Min value = m*g/4 - F/(2x)*(Z+z)
Which shows the force on the bearings could act upwards if the Z axis is long enough, or the bearing spacing is small.
My question is, have I mised anything here in the formulas and what would one normally chose for x in relation to Z:question:
If I put the numbers in for my router (x=0.3, z=0.5 ish), cutting steel, then I get -50N to 200N. Well within the 980N/-340N rating for 25mm bearings...and within rating even for 12mm bearings. I'm not sure which to go for. Two 25mm rails, or maybe get 4 rails and have 16mm...:question:
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