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The only point with the Spindle providing On/Off is the CW/CCW control - if you think you'll use reverse.
You could use the BoB spindle output - it's just another discrete output, but you'll lose the reversing option (assuming the SpindleV5 does 0-10 and separately CW/CCW depending on the DIR input).
Don't expect to want reverse and using the BOB spindle output seems easier than trying to activate the Spindle V5 CW/CCW relays.
Now I am confused. Pins 16 & 17 (spindle on/dir) go from BOB to spindle 5 board but it's the sprint that starts the spindle and I can't see how the sprint gets a signal to start the motor.
My guess?, and it is a guess... the Sprint is configured such that a non-zero demand on the analogue input starts the spindle-motor. That short-cuts the need for a FOR/REV control.
Doesn't work for the Chinese VFD. You still need to source the spindle relay outputs through the BoB (and optionally through the Spindle V5) to the VFD
That's spindle PWM (or Step)/DIR, isn't it? Rather than a discrete ON(/OFF)Quote:
Originally Posted by ngwagwa
Yes
Attachment 25690
What's happening with Pin 5 of the Sprint controller?
Com and run have just over 9 volts all the time
With the pin-out as-shown in the manual there should be approx 5 volts between COM and RUN.Quote:
Originally Posted by ngwagwa
No shorting link between COM and RUN? With power off (and discharged for 20 minutes) what's the resistance between COM and RUN?
This is all a bit of a distraction to explain why the Sprint/Spindle Motor doesn't need a separate signal from the BoB - it's kind of irrelevant - as above you need to source a motor-run from the BoB/SpindleV5
Have now found out there is a jumper removed from the BOB which disables the onboard relay and enables the port used for the Spindle 5.