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  1. #1
    Ahh doddy !
    So simple and straight forward. How could I possibly get it wrong?

    So our friends at Boxford chose a 10v output without any apparent resistor in series? or where did they hide it
    And I guess I will have to use 12v so maybe will have to add a resistor, or maybe 5v but I will need to go back to my 1968 physics A level notes if I really want to understand your calc .

    I can manage most mechanical stuff , and have a reasonable grasp of electrical machines , single and 3 phase, Even managed to get a handle on electronics in the days of thermionic valves , but I have to say that when the world turned upside down, when the time came when current stopped flowing from positive to negative and it was decided instead that current was a stream of negatively charged particles careering towards a positively charged source then that was the time at which my "electronic "head started to hurt .

    What I am saying is you have to bear with me a bit while this stuff sinks in . When I get my new switches, I may need to come back with the spec, and ask you to turn forward voltage and forward current into a suitable source voltage / resistor combination.
    Hope you haven't got too sick of me by that time

  2. #2
    OK so I have ordered new switches and in the meantime had a closer look at these


    Click image for larger version. 

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    So this might be surprising but looks like Boxford have chosen to wire these lamps like xmas tree lamps ie in series .
    So our green supply wire seems to ring around the switch commons then on to the two lamps in series. How do I add the forward voltages in this configuration??

    Now as Inee points out from the Boxford wiring diagram the input voltage is 10v and there is no sign of a resistor . Is it possible that the lamp resistances stack up so that no external resistor is needed . and how would that be affected if i chose to supply 12v?

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