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Thread: Losing steps

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  1. #1
    Quote Originally Posted by Edendale View Post
    but it starts at the right point for the next cut
    That statement requires a bit of elaboration.

    Do you mean (and I'm possibly mis-interpreting your words here), that for each successive pass, the X/Y recovers to the same position (exactly the same position, no 2mm/pass offset)?

    If so, can you post your g-code?

  2. #2
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  3. #3
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  4. #4
    Hi Doddy, I might be wrong about it starting again at the same place it’s hard to tell,

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