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Thread: speed controler

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  1. #1
    should i have continuity across motor + motor - coz i have ? dont think thats right

  2. #2
    m_c's Avatar
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    ptwj's calc is correct for the starting current.
    Power = Current x Voltage, and to get Voltage drop across the resistor, we use Voltage = Current x Resistance

    To get Voltage over the resistor, we use Voltage = Current x Resistance, which is 17A x 0.18 = 3.06V
    Power = 17A x 3.06v = 52.02W.
    For running at the continuous rating, 0.85A x 0.18 = 0.153V x 0.85A = 0.13W
    For running at the intermittent rating, 1.75A x 0.18 = 0.315V x 1.75A = 0.551W
    For startup.......................................17A x 0.18 = 3.06V x 17A = 52.02W

    However, that is the instantaneous power consumption at switch on at full power. The KBIC should slowly ramp up to the set power, to avoid any major inrush issues.

    Quote Originally Posted by Scott View Post
    should i have continuity across motor + motor - coz i have ? dont think thats right
    What do you mean across Motor + Motor?
    On the board, or the motor itself?

  3. #3
    on the speed controler breakout board i have a terminal block motor + motor -
    not the motor ....

    motor not connected

    just used meter on the -/+ terminals for the motor
    Last edited by Scott; 03-11-2010 at 10:19 PM.

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