Thread: speed controler
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03-11-2010 #1
should i have continuity across motor + motor - coz i have ? dont think thats right
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03-11-2010 #2
ptwj's calc is correct for the starting current.
Power = Current x Voltage, and to get Voltage drop across the resistor, we use Voltage = Current x Resistance
To get Voltage over the resistor, we use Voltage = Current x Resistance, which is 17A x 0.18 = 3.06V
Power = 17A x 3.06v = 52.02W.
For running at the continuous rating, 0.85A x 0.18 = 0.153V x 0.85A = 0.13W
For running at the intermittent rating, 1.75A x 0.18 = 0.315V x 1.75A = 0.551W
For startup.......................................17A x 0.18 = 3.06V x 17A = 52.02W
However, that is the instantaneous power consumption at switch on at full power. The KBIC should slowly ramp up to the set power, to avoid any major inrush issues.
What do you mean across Motor + Motor?
On the board, or the motor itself?
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03-11-2010 #3
on the speed controler breakout board i have a terminal block motor + motor -
not the motor ....
motor not connected
just used meter on the -/+ terminals for the motorLast edited by Scott; 03-11-2010 at 10:19 PM.
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