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  1. #1
    Quote Originally Posted by irving2008 View Post
    Assuming those rods are about 500mm between end supports (based on pic 0068 and the size of the platter) the deflection in the centre is around 2um (2 x 1e-6m) per kg

    Won't bow as much as you think because the supports are fixed not simple.

    I'd guess that table weighs 25 - 30kg with the slide mounted - so deflection <0.1mm in the middle...
    Thanks Irving, I was thinking 900+ (based on ruler in pic 0263) and 40-60kgs! The other thing that has thrown me is the feet are not secured to the base...

    Seem to recall seeing a spreadsheet somewhere that someone did for unsupported rail, was it yours?... (of course I cant find it!)

  2. Quote Originally Posted by mocha View Post
    Thanks Irving, I was thinking 900+ (based on ruler in pic 0263) and 40-60kgs! The other thing that has thrown me is the feet are not secured to the base...

    Seem to recall seeing a spreadsheet somewhere that someone did for unsupported rail, was it yours?... (of course I cant find it!)
    Yes it was probably and no i cant find it either...

    900mm would be 12um per kg, so 60kg = 0.7mm assuming the legs dont rotate which is a good point, but they're quite wide . My 300mm was the length the slide is on from the feet furthest from the headstock to the next set, not the whole length. Its a whole new ballgame if you want to include the full length and the other sets of feet and their rotation. But even then it'll be less than 0.7mm which is worst case (unless you assume simple supports but that would be massively incorrect as well).

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