. .

Hybrid View

Previous Post Previous Post   Next Post Next Post
  1. #1
    Quote Originally Posted by Jonathan View Post


    To find the equivalent inertia of the 120kg gantry, you need to consider the effect of the ballscrew, so this formula is required (where L is the pitch of the screw):
    Hi, I would like to apply this to my machine and wonder how it does come from ( see behind the formula)
    That means this is not enough to count the reduced inertia on motor shaft with only the rotating parts?

    120 kg*(0,01/2pi)e^2= 3,4 e-4 differs from your number.
    Where I am wrong -Am I understanding everything well?
    Thanks
    Last edited by vargai; 09-12-2014 at 08:08 AM.

Thread Information

Users Browsing this Thread

There are currently 1 users browsing this thread. (0 members and 1 guests)

Bookmarks

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •