Thread: routercnc_MK3
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13-04-2015 #27
Sounds like it to me.
Sizing the capacitors is quite tricky - there are formulas floating about on forums, but prizes for finding one with some derivation or reference, not just a rule-of-thumb. You can easily calculate the voltage ripple on the capacitors for a known current (V=I/(C*f)), but what current do you use and what voltage ripple is acceptable? We can get a reasonable idea of the input current from the motor power ratings, but even then it's a bit of a guess as to what voltage ripple the stepper driver will tolerate. You could look at it in terms of what voltage (and hence current) ripple the capacitors will tolerate, or define some minimum input voltage from the transformer you'll allow and go from there. I'd probably go with the former...then take an educated guess!
For a while I had my machine running 4 motors from a 500VA transformer with 11000uF capacitance and I noticed an improvement in obtainable feedrates when I moved one motor to another (320VA) transformer and left the original transformer and capacitors with just 3 motors. So maybe 15000uF is fine ... bit subjective though as I didn't take any readings to verify.
That's a shame. Do you have a working CNC router, or is this your first? If you want I can send you the dxf to make these ... it's very simple:
Or we could do some sort of swap.
That's normal - they are a bit high as the rating is when loaded.
Not the case. If you get them the wrong way round, the voltages will cancel out and you'll get approximately zero. I would guess that the order they are written on the label is indicative of their polarity, so try connecting red to orange and measure the open circuit voltage between black and yellow.
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