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29-09-2014 #7
Last Activity: 02-10-2024
These usually take between 12mA and 20mA, as you say a series resistor would do.
Say it's 12mA
R=V/I
(68-24)/0.012 = 3.7 k ohms
watts = IxIxR = 0.54 watts
Say it's 20mA
R=V/I
(68-24)/0.02 = 2.2 k ohms
watts = IxIxR = 0.8 watts
So I'd start with a 3.7k 5watt resistor and measure the voltage across the lamp, if it's too low then try a lower value resistor.
Ah ha, Irving just beat me to it
I chose 5 watts having come through the 'brick shit-house' school of engineering.
Last edited by EddyCurrent; 29-09-2014 at 03:35 PM.
Spelling mistakes are not intentional, I only seem to see them some time after I've posted
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