Hi from Brum

[smeg up]

Ignore the last post (which doesn't look like it displayed for some reason?), just read quickly through the document, I think I am on the right lines now but if someone could check I would be most appreciative, btw, the last reply I think I called you eddy, saw where your nick originates from now so apologies :)

Working out PS.

Running steppers in 2 phase bipolar parallel connection. http://cnc4you.co.uk/resources/Stepp...1B%203.1Nm.pdf

1. AMPS - 3x steppers drawing 4.2 amps. 3 x 4.2 = 12.6A
Because running in parallel amps required from PS should be 2/3 of total = 8.4A
Q. I presume it is ok to up to 10A as the drivers will draw what they need?

2. VOLTAGE - 32 * √L = Vmax
inductange (mH) of 1x stepper is 3.2 +/- 20% so 2.56-3.84mH
using the above, as far as i can see the voltage should be 51.2-62.71V or 57.24V if the stepper is spot on.
Q. So would a 60v 10A PSU be correct? Do i need to multiply the volts by 3 for the other steppers?

Thanks.